Given Q(4;1),T(p;3) and length QT=root of 8 units ,determine the value of p

√( (p-4)^2 + (3-1)^2) )= √8

square both sides
(p-4)^2 + 4 = 8
(p-4)^2 = 12
p-4 = ±√12
p = 4 ± 2√3

1.Seven years ago, Rocco's drum kit cost him R12500.It has now been valued at R2300. What rate of simple depreciation does this represent?

2. Fiona buys a DStv satelite dish for R3000. Due to weathering ,its value depreciates simply at 15% p.a .after how lond will the satellite dish have a book value of zero?

11,65

To determine the value of p, we can use the distance formula to find the distance between points Q(4,1) and T(p,3).

The distance formula is given by:
d = √((x2 - x1)^2 + (y2 - y1)^2)

Given that the length QT is the square root of 8 units, we can set up the equation as follows:

√((p - 4)^2 + (3 - 1)^2) = √8

Simplifying the equation, we have:

(p - 4)^2 + 2^2 = 8

Expanding and simplifying further:

(p - 4)^2 + 4 = 8

(p - 4)^2 = 4

Taking the square root of both sides:

p - 4 = ±2

Now we can solve for p:

p - 4 = 2 or p - 4 = -2

Solving for p in each equation:

p = 2 + 4 = 6 or p = -2 + 4 = 2

So, the possible values of p are 6 and 2.