math
posted by perfect .
Given Q(4;1),T(p;3) and length QT=root of 8 units ,determine the value of p

√( (p4)^2 + (31)^2) )= √8
square both sides
(p4)^2 + 4 = 8
(p4)^2 = 12
p4 = ±√12
p = 4 ± 2√3 
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