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solve my system of equation with full steps
3x+4y=29
2x–5y=-19

  • math -

    Multiply I eq by 2 and II by 3
    6x+8y=58
    6x-15y=-57. Subtract II eq from I. Signs of II eq will change:-6x+15y=57.

    Thus, 8y+15y=58+57 Or 23y=115
    or y=115/23=5.
    Now substitute this in any original eq:
    3x-4x5=29 or 3x=29-20=9, hence x=9/3=3

  • math -

    6,-1

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