posted by isaac
tap a was turned on to fill a rectangular tank of 50cm by 40cm by 28cm with water at a rate of 6 liters per minute. after 2 minutes, tap b was turned on to drain water from the tank at a rate of 2 liters per minutes. 6 minutes after tap b was turned on, both taps were tuned off. find the depth of water left in the tank
Tap a filled for 8 mins=8x6=48 lit.
Tap b drained for 6 mins=6x2=12 lit.
Water remaining=48-12=36 lit=36000ml
Ht of water in tank=36000/(50x40)=36/2=18 cm
A full tank will hold 56 L
Using the calculations of anonymous of 36 L of water after both taps are turned of,
h/28 = 36/56
h = 28(36/56) = 18
the water is 18 cm deep
Trig aplication meseramants width of lake
Haw can solev this qen trig application measruments width of lake?