True or False. The value of the square root of 16 is greater than the cube root of 29.
Well, √16 = 4
I know the cube root of 27 is 3
and the cube root of 64 is 4
so the cube root of 29 must be between 3 and 4, with just a bit over 3
mmmhhh?
To determine whether the statement is true or false, we need to compare the value of the square root of 16 with the cube root of 29.
First, we'll find the value of the square root of 16. The square root of a number gives us a value that, when squared, equals the original number. In this case, the square root of 16 is 4 because 4 * 4 = 16.
Next, we'll find the value of the cube root of 29. The cube root of a number gives us a value that, when cubed, equals the original number. We can use a calculator or estimation to find this value. After calculating, we find that the cube root of 29 is approximately 3.079.
Now, we can compare the two values. Is 4 greater than 3.079? Yes, 4 is greater than 3.079.
Therefore, the statement "The value of the square root of 16 is greater than the cube root of 29" is True.