Calculate the percent yield for the reaction if 76.8 g of H2O reacted and 125 g of NO were produced.

NO2+H2O->HNO3+NO

Use simple stoichiometry (as in the last post) to find grams NO produced. This is the theoretical yield (TY). The ctual yield (AY) is 76.9g.

%yield = (AY/TY)*100 = ?

To calculate the percent yield for a reaction, you need to compare the actual yield to the theoretical yield.

Step 1: Calculate the molar mass of H2O (18.015 g/mol) and NO (30.01 g/mol).

Step 2: Convert the given mass of H2O to moles using the molar mass:
76.8 g H2O * (1 mol H2O/18.015 g H2O) = 4.27 mol H2O

Step 3: Write a balanced equation and determine the stoichiometry:
NO2 + H2O -> HNO3 + NO
From the balanced equation, the stoichiometry of H2O to NO is 1:1.

Step 4: Calculate the theoretical yield of NO based on the balanced equation and moles of H2O:
4.27 mol H2O * (1 mol NO/1 mol H2O) = 4.27 mol NO

Step 5: Convert the theoretical yield of NO to grams using the molar mass:
4.27 mol NO * (30.01 g NO/1 mol NO) = 128.11 g NO

Step 6: Calculate the percent yield by dividing the actual yield by the theoretical yield and multiplying by 100:
Percent yield = (actual yield / theoretical yield) x 100
Percent yield = (125 g NO / 128.11 g NO) x 100 = 97.56%

Therefore, the percent yield for the reaction is 97.56%.

To calculate the percent yield, you need to compare the amount of product actually obtained (in this case, the 125 g of NO) to the theoretical yield.

The theoretical yield is the maximum amount of product that can be obtained from a given amount of reactant, assuming 100% efficiency. In order to determine the theoretical yield, we need to calculate the stoichiometric ratio between H2O and NO in the balanced chemical equation.

The balanced equation is:
NO2 + H2O -> HNO3 + NO

From the balanced equation, we can see that the molar ratio of H2O to NO is 1:1. This means that for every 1 mole of H2O that reacts, 1 mole of NO is produced.

Now, let's calculate the number of moles of H2O:
Molar mass of H2O = 2(g/mol) + 16(g/mol) = 18(g/mol)
Number of moles of H2O = Mass of H2O / Molar mass of H2O
= 76.8(g) / 18(g/mol)
= 4.27(mol)

Since the molar ratio of H2O to NO is 1:1, the number of moles of NO produced is also 4.27.

Now, let's calculate the theoretical yield of NO:
Molar mass of NO = 14(g/mol) + 16(g/mol) = 30(g/mol)
Mass of NO = Number of moles of NO * Molar mass of NO
= 4.27(mol) * 30(g/mol)
= 128.1(g)

The theoretical yield of NO is 128.1 g.

Finally, we can calculate the percent yield using the formula:
Percent Yield = (Actual Yield / Theoretical Yield) * 100

Plugging in the values:
Percent Yield = (125(g) / 128.1(g)) * 100
= 97.6%

Therefore, the percent yield of the reaction is 97.6%.