math
posted by Anonymous .
The area of a rectangle is 72 square inches and the perimeter is 44 inches. Find its dimensions.

area=lw
lw=72 or l=72/w
P=2(l+w)=2(72/w + w)
44=2(72/w+w)
22w=7+w^2
w^222w+72=0
(w18)(w4)=0
so w is 18, or 4, and you can solve for the length from l=72/w