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physics

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In 0.511 s, a 13.1-kg block is pulled through a distance of 3.13 m on a frictionless horizontal surface, starting from rest. The block has a constant acceleration and is pulled by means of a horizontal spring that is attached to the block. The spring constant of the spring is 466 N/m. By how much does the spring stretch?

  • physics -

    F=ma=kx

    k=ma/x

    so what is acceleration a?

    vaverage=3.13m/.511s
    vfinal then must be twice that, or 6.26/.511

    but we know
    Vfinal^2=Vi^2+2ad so solve for a

    Then, solve for k from k=ma/x

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