Post a New Question


posted by .

In 0.511 s, a 13.1-kg block is pulled through a distance of 3.13 m on a frictionless horizontal surface, starting from rest. The block has a constant acceleration and is pulled by means of a horizontal spring that is attached to the block. The spring constant of the spring is 466 N/m. By how much does the spring stretch?

  • physics -



    so what is acceleration a?

    vfinal then must be twice that, or 6.26/.511

    but we know
    Vfinal^2=Vi^2+2ad so solve for a

    Then, solve for k from k=ma/x

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question