Four candidates are running for president of the student council. Three other candidates are running for vice-president. How many different ways can the two offices be filled?
4*3 = ?
12
To find the number of different ways the two offices can be filled, we can use the concept of permutations.
First, we need to determine how many options there are for the president's position. Since there are four candidates running for president, we have 4 choices.
Next, we need to determine how many options there are for the vice-president's position. Since there are three candidates running for vice-president, we have 3 choices.
To determine the total number of ways, we multiply the number of choices for each position together: 4 choices for the president × 3 choices for the vice-president.
Therefore, there are 4 × 3 = 12 different ways the two offices can be filled.