# solubility

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The Ksp of mercury II hydroxide is 3.60 x 10^-26. Calculte the solubility of this compound in g/L

• solubility -

...........Hg(OH)2 ==> Hg^2+ + 2OH^-
I..........solid.......0........0
C............-x........x........2x
E..........solid.......x........2x

x = solubility
Ksp = (Hg^2+)(OH^-)^2
Substitute the E line and solve for x = solubility in mols/L, then convert to g/L.

• solubility -

1.09*10^-74

• solubility -

• solubility -

Actually both are wrong the answer is 1.69*10 to the power -7. Trust me I got the answer write on sapling

• solubility -

4.86*10^7 is correct. I also go it right on Sapling. x=2.09*10^-9 multiply by Molar Mass 234.605

• solubility -

2.08*10^-9

• solubility -

4.88*10^7

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