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solubility

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The Ksp of mercury II hydroxide is 3.60 x 10^-26. Calculte the solubility of this compound in g/L

  • solubility -

    ...........Hg(OH)2 ==> Hg^2+ + 2OH^-
    I..........solid.......0........0
    C............-x........x........2x
    E..........solid.......x........2x

    x = solubility
    Ksp = (Hg^2+)(OH^-)^2
    Substitute the E line and solve for x = solubility in mols/L, then convert to g/L.

  • solubility -

    1.09*10^-74

  • solubility -

    4.86*10^-7 is the real answer

  • solubility -

    Actually both are wrong the answer is 1.69*10 to the power -7. Trust me I got the answer write on sapling

  • solubility -

    4.86*10^7 is correct. I also go it right on Sapling. x=2.09*10^-9 multiply by Molar Mass 234.605

  • solubility -

    2.08*10^-9

  • solubility -

    4.88*10^7

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