# algebra

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A bank teller has 35 bills in \$5, \$10, and \$20 denominations. The total value from these bills is \$370.The total number of \$10 bills and \$20 bills is 7more than the number of \$5. How many bills of each denomination?

• algebra -

No. of \$5=bills a, \$10 bill=b and \$20 bill=c
Then a+b+c=35
5a+10b+20c=370, and
b+c=a+7.

Substituting value of b+c in first eq.,
a+(a+7)=35 or 2a=28 or a=14 and
b+c=35-14=21.
Substituting value of a in second eq., 14x5+10b+20c=370 or 10b+20c=370-70
Or 10b+20c=300 or b+2c=30
Subtract from this the eq. b+c=21 and we get c=30-21=9. thus b=35-14-9=12.
Check:14x5+12x10+9x20=370
70+120+180=370 OK.

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