What mass of KCl in grams is formed when 2.00 lbs of KC103 is decomposed?

KClO3 --> KCl + O2

Balanced the equation.

2KClO3 ==> 3O2 + 2KCl
Convert lbs KClO3 to grams. There are 453.6 grams/lb.
mols KClO3 = grams/molar mass
Using the coefficients in the balanced equation, convert mols KClO3 to mols KCl.
Now convert mols KCl to grams. g = mopls x molar mass.

How many grams of NaOH would be needed to react with 199 g of HCl?

NaOH + HCl --> NaCl + H2O

To find the mass of KCl formed, we need to use the given information that 2.00 pounds of KClO3 is decomposed.

First, let's convert the mass from pounds to grams, since the molar mass is given in grams. We know that 1 pound is equal to 453.592 grams.

2.00 pounds * 453.592 grams/pound = 907.184 grams

So, we now have 907.184 grams of KClO3.

Next, we need to find the molar mass of KClO3 and KCl to determine the mole ratio between the two compounds.

The molar mass of KClO3:
K: 39.10 g/mol
Cl: 35.45 g/mol
O: 16.00 g/mol (there are three oxygen atoms)
Total molar mass of KClO3 = 39.10 + 3(16.00) + 35.45 = 122.55 g/mol

The molar mass of KCl:
K: 39.10 g/mol
Cl: 35.45 g/mol
Total molar mass of KCl = 39.10 + 35.45 = 74.55 g/mol

Now we can determine the mole ratio between KClO3 and KCl by comparing their molar masses:
1 mol KClO3 = 122.55 g KClO3
x mol KClO3 = 907.184 g KClO3 (mass of KClO3 given)

x = (907.184 g KClO3) / (122.55 g/mol KClO3)
x ≈ 7.40 mol KClO3

Using the mole ratio from the balanced equation, we know that for every 1 mole of KClO3 decomposed, 1 mole of KCl is formed.

So, the number of moles of KCl formed is also 7.40 mol.

Finally, to find the mass of KCl formed, we multiply the number of moles by the molar mass of KCl:
Mass = moles * molar mass
Mass of KCl = 7.40 mol * 74.55 g/mol
Mass of KCl ≈ 550.37 grams

Therefore, approximately 550.37 grams of KCl are formed when 2.00 pounds of KClO3 is decomposed.