# Elementary mechanics

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Given that the mass and radius of jupiter are respectively 190000000kg 7150000km.Calculate the escape velocity from the surface of the planet(a)11.2 km/s(b)33.3km/s(c)59.5km/s(d)110.4km/s

• Elementary mechanics -

the gravitational constant
G =6.67•10⁻¹¹ N•m²/kg²,
M=1.9•10²⁷ kg !!!!!!!!!!!!
R=7.15•10⁷ m !!!!!!!!
v=sqrt(2GM/R)=
=59539 m/s ≈59.5 km/s

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