Elementary mechanics

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Given that the mass and radius of jupiter are respectively 190000000kg 7150000km.Calculate the escape velocity from the surface of the planet(a)11.2 km/s(b)33.3km/s(c)59.5km/s(d)110.4km/s

  • Elementary mechanics -

    the gravitational constant
    G =6.67•10⁻¹¹ N•m²/kg²,
    M=1.9•10²⁷ kg !!!!!!!!!!!!
    R=7.15•10⁷ m !!!!!!!!
    v=sqrt(2GM/R)=
    =59539 m/s ≈59.5 km/s

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