the distance between two stations is 340 km two trains start simultaneously on parallel tracks to each other . the speed of one of them is greater than that of the other by 5 km/hr. if the distance between the two trains after 2 hrs of their start is 30 km , find the speed of each train
Two trains with speeds s and s+5 km/hr.
Initial distance=340 km
final distance = 30 km
Total distance travelled = 340-30=310 km
Total speed = s+s+5=2s+5
Time = 2 hrs
Form equation equating distance travelled
Time*speed=distance, or
2(2s+5)=310
2s+5=155
2s=150
s=75
Speeds of trains are 75 km/h and 80 km/hr
If one train has a velocity of V km/h, the other one will have velocity V+5 km/h approaching the first train. Therefore Relative velocity will be V+V+5=2V+5 km/h.
Distance travelled by them in 2 hrs is 340-30=310km which is =2(2V+5)
Thus 4V+10=310 or 4V=300 hence V=75km/h and other train has a velocity of 80km/h.
Check: in 2 hrs they will move 75x2+80x2=150+160=310km =340-30 km. OK.
Please explain me distance travel in 2 hr=340-30 please
Thank you
Dog water
To find the speeds of the two trains, let's break down the information given:
Distance between the two stations = 340 km.
Time elapsed = 2 hours.
Let's assume the speed of the slower train is "x" km/hr.
Therefore, the speed of the faster train is "x + 5" km/hr.
We are also given that after 2 hours, the distance between the two trains is 30 km.
To find the speeds of the trains, we can use the formula: Speed = Distance / Time.
Speed of the slower train = 30 km / 2 hours = 15 km/hr.
Using this speed and the given relationship (x + 5), we can create an equation:
x + 5 = 15.
Solving this equation, we find:
x = 10 km/hr.
So, the speed of the slower train is 10 km/hr, and the speed of the faster train is 15 km/hr.