algebra
posted by angela .
Solve the system using elimination
X+3y=5
4x+4y=4 I tried to work this problem and
this is what I came up with.
x+3y=5
x+4y=20
7y=15
y=7/15
and x= (5+y)/4
(5+7/15)/2
2/15
x=2/15
x=2/15, y=7/15 I would like for someone to check to see if it is correct.

Please see your third line: It should be
4y3y=205 or y=15, by subtracting first equation from second.
Now x+3*15=5
Or x=545=40. Check:40+4*15=20 by putting values in second equation.
This 40=1560=40 OK.
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