Solve the system using elimination

X+3y=5
4x+4y=4 I tried to work this problem and
this is what I came up with.
x+3y=5
x+4y=20
7y=15
y=7/15

and x= (5+y)/4
(5+7/15)/2
2/15
x=2/15

x=2/15, y=7/15 I would like for someone to check to see if it is correct.

Please see your third line: It should be

4y-3y=20-5 or y=15, by subtracting first equation from second.
Now x+3*15=5
Or x=5-45=-40. Check:-40+4*15=20 by putting values in second equation.
This -40=15-60=-40 OK.

To solve the system using elimination, you need to eliminate one variable by multiplying the equations so that the coefficients of one variable are equal in both equations. Let's go through the solution step by step:

Given system of equations:
1) x + 3y = 5
2) 4x + 4y = 4

To eliminate the variable x, we need to manipulate the equations so that the coefficients of x are the same or the additive inverse of each other.

To achieve this, we can multiply equation 1 by 4 and equation 2 by 1, so that the coefficients of x become equal:
4 * (x + 3y) = 4 * 5
1 * (4x + 4y) = 1 * 4

Simplifying these equations:
4x + 12y = 20
4x + 4y = 4

Now, subtract equation 2 from equation 1 (4x - 4x = 0x cancels out):
(4x + 12y) - (4x + 4y) = 20 - 4

Simplifying and solving for y:
8y = 16
y = 16/8
y = 2

Now that we have a value for y, we can substitute it back into either of the original equations to find the value of x. Let's use equation 1:

x + 3(2) = 5
x + 6 = 5
x = 5 - 6
x = -1

The solution to the system of equations is:
x = -1, y = 2.

Therefore, it seems like there was an error in your calculations. The correct solution to the system is x = -1 and y = 2.