A piece of luggage is being loaded onto an airplane by way of an inclined conveyor belt. The bag, which has a mass of 10.0 kg, travels 6.50 m up the conveyor belt at a constant speed without slipping. If the conveyor belt is inclined at a 60.0° angle, calculate the work done on the bag by: The force of gravity (g), the normal force (N), the friction force (f), the conveyor belt, and the net force.

sloppy work henry

Wt. = m*g = 10kg * 9.8N/kg = 98 N. = Wt.

of the luggage.

F = 98N.[60o] = Force of luggage.
Fp = 98*sin60 = 84.9 N. = Force parallel to incline.
Fv=98*cos60 = 49 N.=Force perpendicular to incline = Normal.

a. Work=mg * h = 98 * 6.5sin60= 552 J.

b. Work = -98 * 6.5sin60 = -552 J.

c. Work = Fk * d = 0 * 6.5 = 0.

d. Work = Fn*d = 84.9 * 6.5 = 552 J.

work by conveyer belt = work of normal + work of friction force why i don't know its dumb.

To calculate the work done on the bag by each force, we need to first determine the magnitude of each force. Let's start with the force of gravity.

1. Force of gravity (mg):
The force of gravity is equal to the mass of the object multiplied by the acceleration due to gravity (9.8 m/s^2). In this case, the mass of the bag is given as 10.0 kg.
So, F_gravity = (10.0 kg) x (9.8 m/s^2)

Next, let's find the normal force (N) exerted on the bag by the inclined conveyor belt.

2. Normal force (N):
The normal force is the force exerted perpendicularly by the surface (in this case, the conveyor belt) to support the weight of the object. Since the bag is not slipping, the normal force will be equal in magnitude but opposite in direction to the force of gravity.
So, N = -F_gravity (magnitude)

Now, let's calculate the frictional force (f) between the bag and the conveyor belt.

3. Frictional force (f):
The frictional force will be the force required to prevent the bag from sliding down the inclined conveyor belt. It can be calculated using the equation: f = μsN, where μs is the coefficient of static friction between the bag and the conveyor belt.
Since the bag is moving at a constant speed without slipping, the frictional force is equal in magnitude but opposite in direction to the force exerted by the conveyor belt.
So, f = -F_conveyor_belt (magnitude)

Finally, let's find the net force exerted on the bag.

4. Net force:
The net force is the vector sum of all the forces acting on the object. Since the bag is moving at a constant velocity, the net force should be zero.
So, F_net = 0

To calculate the work done on the bag by each force, we can use the equation: Work = Force x Displacement x cosθ, where θ is the angle between the force and the displacement.

Work done by the force of gravity:
W_gravity = F_gravity x displacement x cos(180°)

Work done by the normal force:
W_normal = F_normal x displacement x cos(180°)

Work done by the frictional force:
W_friction = F_friction x displacement x cos(180°)

Work done by the conveyor belt:
W_conveyor_belt = F_conveyor_belt x displacement x cos(0°)

Since the net force is zero, no work is done by the net force.

Please provide the value for μs (coefficient of static friction) and the displacement (6.50 m), so that I can calculate the work done by each force.