Physics
posted by Briana .
A 1.2 kg object is moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 6.0m/s in the opposite direction perpendicular to the wall. If the object is in contact with the wall for 2.0m/s. What is the magnitude of the average force on the object by the wall?

8.4Kn

Could you please explain how you got to your answer?

F=Δp/Δt=mΔv/Δt=
=m[v₂(v₁)]/Δt=
=m(v₂+v₁)/Δt=
=1.2•(6+2)/ Δt=…
Check the given data (time of contact!!!!)and substitute it
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