A tennis ball may leave the racket on a serve by a top player with a speed of 45.0 m/s. If the ball's mass is 0.063 kg, and it is in contact with the racket for 0.030 s, what is the average force (in newtons) on the ball?
F=Δp/Δt=mΔv/Δt=
=0.063•45/0.03=94.5 N
To find the average force on the ball, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
To determine the acceleration of the ball, we can use the equation of motion:
v = u + at
where:
- v is the final velocity (45.0 m/s)
- u is the initial velocity (0 m/s)
- a is the acceleration (unknown)
- t is the time (0.030 s)
Rearranging the equation, we have:
a = (v - u) / t
a = (45.0 m/s - 0 m/s) / 0.030 s
a = 1500 m/s^2
Now that we have the acceleration, we can calculate the force using Newton's second law:
F = m * a
F = 0.063 kg * 1500 m/s^2
F = 94.5 N
Therefore, the average force on the ball is 94.5 Newtons.