two forces f1 and f2 acting on an object at a 90 degree angle will pull the object with a reluctant force, R, at an angle between f1 and f2. R= �ã
f1^2+f2^2
R=15 and f1=9 find f2
R=√(f1^2 + f2^2)
So, plug in your knows and solve for the unknown:
15 = √(9^2 + f2^2)
225 = 81 + f2^2
This is algebra I, so should pose no problem to one studying calculus...
To find the value of f2, given R = 15 and f1 = 9, we can use the formula R = √(f1^2 + f2^2).
Substitute the given values into the formula:
15 = √(9^2 + f2^2)
To solve for f2, we need to isolate f2^2. Square both sides of the equation:
15^2 = (9^2 + f2^2)^2
225 = 81 + f2^2
Now, move 81 to the left-hand side of the equation:
225 - 81 = f2^2
Expand and simplify:
144 = f2^2
To find f2, take the square root of both sides:
f2 = √144
f2 = 12
Therefore, f2 has a value of 12.