An 8 kg ball is moving at 4 m/s. Work is done on the ball to give it a speed of 12 m/s. What is the ball's initial kinetic energy? What is the ball's final kinetic energy? What work was done on the ball?
KE(ini) =mv₁2 =8•4²/2=…
KE(fin)= mv₂²/2 =8•12²/2=….
W= KE(fin)- KE(ini)= …
KE(ini) =mv₁²/2 =8•4²/2=…
thekinetic energybefore and afater the collision
You did not mention any collision in the problem statement. Can you please provide more information so that I can help you accurately?
To find the ball's initial kinetic energy, you can use the formula:
Kinetic Energy = (1/2) * mass * velocity^2
Given that the mass of the ball is 8 kg and the initial velocity is 4 m/s, we can calculate the initial kinetic energy as follows:
Initial Kinetic Energy = (1/2) * 8 kg * (4 m/s)^2
= (1/2) * 8 kg * 16 m^2/s^2
= 64 J
Therefore, the ball's initial kinetic energy is 64 Joules.
To find the ball's final kinetic energy after the work is done on it, we can use the same formula:
Final Kinetic Energy = (1/2) * mass * velocity^2
Given that the ball's mass remains the same at 8 kg and the final velocity is 12 m/s, we can calculate the final kinetic energy as follows:
Final Kinetic Energy = (1/2) * 8 kg * (12 m/s)^2
= (1/2) * 8 kg * 144 m^2/s^2
= 576 J
Therefore, the ball's final kinetic energy is 576 Joules.
To find the work done on the ball, we can use the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.
Work = Change in Kinetic Energy
Given that the initial kinetic energy is 64 J and the final kinetic energy is 576 J, the work done on the ball can be calculated as:
Work = Final Kinetic Energy - Initial Kinetic Energy
= 576 J - 64 J
= 512 J
Therefore, the work done on the ball is 512 Joules.