what happens when lead nitrate react with
potassium hydroxide
it gives pbi2
hdj
When lead nitrate (Pb(NO3)2) reacts with potassium hydroxide (KOH), a double displacement reaction occurs. The lead cation (Pb2+) from lead nitrate combines with the hydroxide anion (OH-) from potassium hydroxide to form lead(II) hydroxide (Pb(OH)2), while the potassium cation (K+) from potassium hydroxide combines with the nitrate anion (NO3-) from lead nitrate to form potassium nitrate (KNO3).
The balanced chemical equation for the reaction is as follows:
Pb(NO3)2 + 2KOH → Pb(OH)2 + 2KNO3
To determine the products of the reaction, we must consider the charges of the ions involved. Lead(II) has a charge of +2, while hydroxide has a charge of -1. Therefore, it takes two hydroxide ions to balance the charge of one lead ion, resulting in the formation of lead(II) hydroxide. Potassium has a charge of +1, and nitrate has a charge of -1, so they combine in a 1:1 ratio to form potassium nitrate.
To perform the reaction, you would mix a solution of lead nitrate with a solution of potassium hydroxide. The solid lead nitrate would dissolve in water to form a solution, as would the solid potassium hydroxide. When the two solutions are mixed, a white precipitate of lead(II) hydroxide would form, while the potassium nitrate remains dissolved in the solution.
It is important to note that lead(II) hydroxide is insoluble in water and forms a white precipitate. Potassium nitrate, on the other hand, is soluble in water and remains dissolved.
You know, I had no idea what the reaction was, but it took about one minute online to discover
Pb(NO3)2(aq) + 2KOH(aq) -> 2KNO3(aq) + Pb(OH)2(s)
You might try something like that before posting such a problem.