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a ladder 25ft long leans against a wall with its foot on level ground 7ft from the base of the wall. If the foot is pulled away from the wall at the rate 2 ft/s express the distance (y) of the top of the ladder above the ground as a function of the time, t seconds in moving

  • Maths -

    x^2 + y^2 = 625
    x = 2t

    y^2 = 625 - 4t^2
    y = √(625-4t^2)

  • Maths -

    x^2 + y^2 = 625 (Path. theorem)
    x = 7+2t

    (7+2t)^2 + y^2 = 625
    y^2 = 625 -(7+2t)^2
    y=√625 -(7+2t)^2

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