physics
posted by simon .
A 17kg sled is being pulled along the horizontal snowcovered ground by a horizontal force of 29 N. Starting from rest, the sled attains a speed of 2.1 m/s in 9.6 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.

V^2 = Vo^2 + 2a*d
a=(V^2Vo^2)/2
a = ((2.1)^20)/19.2=0.230 m/s^2
Fn = m*a
(FapFk) = m*a
(29Fk) = 17*0.230
29Fk = 3.91
Fk = 293.91 = 25.1 N.
Ws = m*g = 17kg * 9.8N/kg = 167 N. =
Wt. of sled.
u = Fk/Ws = 25.1/167 = 0.150 = Coefficient of kinetic friction.
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