# physics

posted by simon

A 17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 29 N. Starting from rest, the sled attains a speed of 2.1 m/s in 9.6 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.

1. Henry

V^2 = Vo^2 + 2a*d
a=(V^2-Vo^2)/2
a = ((2.1)^2-0)/19.2=0.230 m/s^2

Fn = m*a
(Fap-Fk) = m*a
(29-Fk) = 17*0.230
29-Fk = 3.91
Fk = 29-3.91 = 25.1 N.

Ws = m*g = 17kg * 9.8N/kg = 167 N. =
Wt. of sled.

u = Fk/Ws = 25.1/167 = 0.150 = Coefficient of kinetic friction.

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