math

posted by .

find all nonnegative integer solutions of the system
x+y<8
x+t<8
t+y<8
z+t<8

  • math -

    if t=0, we have
    x<8
    y<8
    z<8
    x+y<8
    so, 0<x<8, y<8-x, z<8
    List them all.

    If t=1, change the 8's to 7's in the first 3 conditions.

    And so on, up to t=7:
    x<1
    y<1
    z<1
    x+y<8
    (x,y,z,t) = (0,0,0,7)

    Don't see the point of the exercise, but there it is.

  • math -

    sory a mistake, the corect one problem is find all nonnegative integer solutions of the system
    x+y<8
    x+Z<8
    t+y<8
    z+t<8

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. math,correction

    Find four solutions for the equation 3x+5y=15 so the equation will turn to be y=-(3)/(5)x+ (3) and when i do the table i get these points for the solution (-2,4.2),(-1,3.60),(0,3),(1,1.8) ok Let me give you a help. Take the slope, …
  2. Math

    determine whether the system of alinear equqtion has one and only one solutions or no solutions find all solutions whenever they exits 3x- 4y =12 6x -8y =24
  3. Math

    Find all solutions of the equation (sec(x))^2−2=0 The answer is A+Bk where k is any integer and 0<A<pi/2 Find: A= pi/4?
  4. math

    Find all solutions of the equation tan^5 x - 9tan x =0. The answer is Ak\pi where k is any integer, the constant A=?
  5. MATH

    Find all solutions of the equation tan^5 x - 9tan x =0. The answer is Ak\pi where k is any integer, the constant A=?
  6. math

    find all nonnegative integer solutions of the system x+y<8 x+z<8 t+y<8 z+t<8
  7. DISCRETE MATHS

    We need to show that 4 divides 1-n2 whenever n is an odd positive integer. If n is an odd positive integer then by definition n = 2k+1 for some non negative integer, k. Now 1 - n2 = 1 - (2k+1)2 = -4k2-4k = 4 (-k2-4k). k is a nonnegative …
  8. 7th grade math

    consider the inequality 2x+3≤-3. Find the set of all integer solutions of this inequality that are also solutions of the inequality 5x-2<3. Please help I am really confuded
  9. Math

    Given a fixed positive integer k > 1, find all integer solutions to the equation y^k = x^2 + x. (x^y means x to the power of y)
  10. math

    The equations x+ ky + 2z =0 x + (2k-1)y + 3z =0 x + ky + (k+3)z = 2k-1 Find the values of k such that a) the system has a unique solution b) the system has no solutions c) the system has infinitely many solutions THANKS

More Similar Questions