(pls help) algebra
posted by david .
4x+y32=1, 6xy4z=7, 10x+2y6z=5 pls show me how to solve for x,y,z. Ans:xx=1.5,y=2,z=1

here are several ways to do this (as I'm sure your textbook will show  read it, and do web searches for alternate presentations).
Substitution:
(1) 4x+y3z = 1
(2) 6xy4z = 7
(3) 10x+2y6z = 5
From (1) we see that y = 4x+3z+1, so plug that into (2) and (3):
6x  (4x+3z+1)  3z = 7
10x + 2(4x+3z+1)  6z = 5
or
(4) 10x 6z = 8
(5) 2x = 3
From (5) we see x = 3/2
Plug that into (4) and z = 1
Plug x and z into any of the original equations and y = 2
Besides substitution, there's elimination, determinants, matrices, and other methods. 
Extra credit: find and fix my typo.