Solve the following system of equations using the cross multiplication method,ax+by=a-b;bx-ay=a+b
http://www.mathcaptain.com/algebra/simultaneous-equations.html
ax +by =a-b
bx-ay=a+b
ax+by +(b-a) = 0
bx –ay +(-a-b) = 0
x y 1
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b ↘ b-a ↘ a ↘ b
-a ↗ -a-b ↗ b ↗ -a
x/{-ab-b²+ab-a²} = y/{b²-ab+a²+ab} = 1/{-a²-b²},
x/{-a²-b²} = 1/{-a²-b²},
x=1.
y/{b² +a²} =1/{-a²-b²},
y=-1.