Math
posted by Lavinia .
Solve the following system of equations using the cross multiplication method,ax+by=ab;bxay=a+b

http://www.mathcaptain.com/algebra/simultaneousequations.html
ax +by =ab
bxay=a+b
ax+by +(ba) = 0
bx –ay +(ab) = 0
x y 1

b ↘ ba ↘ a ↘ b
a ↗ ab ↗ b ↗ a
x/{abb²+aba²} = y/{b²ab+a²+ab} = 1/{a²b²},
x/{a²b²} = 1/{a²b²},
x=1.
y/{b² +a²} =1/{a²b²},
y=1.