f(x)=x^2/(x-2)^3
is this function odd even or neither?
f(-x) = (-x)^2/((-x)-2)^3 = x^2/(-x-2)^3 = -x^2/(x+2)^3
If even, f(-x) = f(x)
If odd, f(-x) = -f(x).
So, neither even nor odd.
is this function odd even or neither?
If even, f(-x) = f(x)
If odd, f(-x) = -f(x).
So, neither even nor odd.