I am having trouble getting the Net ionic equation for:
1)MgSO4 + Na3PO4=
2)Na2CO3 + ZnCl2=
3)Na2CO3 + Na3PO4=
4) Na3PO4 +ZnCl2=
Mg^2+ + PO4^3- ==> Mg3(PO4)2(s). You balance.
Zn^2+ + CO3^2- ==> ZnCO3
3. no reaction
4. PO4^3- + Zn^2+ ==> Zn3(PO4)2(s) You balance.
To determine the net ionic equation for each of the given reactions, you'll need to first write out the balanced molecular equation, and then proceed to identify the spectator ions and cancel them out in the net ionic equation. Here's how you can solve each of the given reactions:
1) MgSO4 + Na3PO4:
Step 1: Write the balanced molecular equation.
MgSO4 (aq) + Na3PO4 (aq) → Mg3(PO4)2 (s) + Na2SO4 (aq)
Step 2: Split the strong electrolytes into their individual ions.
MgSO4 (aq) → Mg2+ (aq) + SO4²¯ (aq)
Na3PO4 (aq) → 3Na+ (aq) + PO4³¯ (aq)
Mg3(PO4)2 (s) remains unchanged since it is a solid.
Step 3: Write the net ionic equation by canceling out spectator ions.
Net ionic equation: Mg2+ (aq) + PO4³¯ (aq) → Mg3(PO4)2 (s)
2) Na2CO3 + ZnCl2:
Step 1: Write the balanced molecular equation.
Na2CO3 (aq) + ZnCl2 (aq) → ZnCO3 (s) + 2NaCl (aq)
Step 2: Split the strong electrolytes into their individual ions.
Na2CO3 (aq) → 2Na+ (aq) + CO3²¯ (aq)
ZnCl2 (aq) → Zn²+ (aq) + 2Cl¯ (aq)
ZnCO3 (s) remains unchanged since it is a solid.
Step 3: Write the net ionic equation by canceling out spectator ions.
Net ionic equation: Zn²+ (aq) + CO3²¯ (aq) → ZnCO3 (s)
3) Na2CO3 + Na3PO4:
Step 1: Write the balanced molecular equation.
Na2CO3 (aq) + Na3PO4 (aq) → Na2PO4 (aq) + Na2CO3 (aq)
Step 2: Split the strong electrolytes into their individual ions.
Na2CO3 (aq) → 2Na+ (aq) + CO3²¯ (aq)
Na3PO4 (aq) → 3Na+ (aq) + PO4³¯ (aq)
Na2PO4 (aq) remains unchanged since it is soluble.
Step 3: Write the net ionic equation by canceling out spectator ions.
Net ionic equation: None. Both the reactants and products are soluble, so they remain fully dissociated into ions. There is no net ionic equation for this reaction.
4) Na3PO4 + ZnCl2:
Step 1: Write the balanced molecular equation.
Na3PO4 (aq) + ZnCl2 (aq) → Zn3(PO4)2 (s) + 6NaCl (aq)
Step 2: Split the strong electrolytes into their individual ions.
Na3PO4 (aq) → 3Na+ (aq) + PO4³¯ (aq)
ZnCl2 (aq) → Zn²+ (aq) + 2Cl¯ (aq)
Zn3(PO4)2 (s) remains unchanged since it is a solid.
Step 3: Write the net ionic equation by canceling out spectator ions.
Net ionic equation: 3Na+ (aq) + 2Cl¯ (aq) → 6NaCl (aq)
To find the net ionic equation for these reactions, we need to first write the balanced molecular equation and then proceed with the steps to convert it into the net ionic equation.
1) MgSO4 + Na3PO4:
Step 1: Write the balanced molecular equation.
MgSO4 + Na3PO4 → Mg3(PO4)2 + Na2SO4
Step 2: Break down all the ionic compounds into their respective ions.
MgSO4(aq) → Mg2+(aq) + SO4^2-(aq)
Na3PO4(aq) → 3Na+(aq) + PO4^3-(aq)
Mg3(PO4)2(aq) → 3Mg2+(aq) + 2PO4^3-(aq)
Na2SO4(aq) → 2Na+(aq) + SO4^2-(aq)
Step 3: Remove the spectator ions, the ions that appear unchanged on both sides of the equation.
In this case, the spectator ions are Na+ and SO4^2-.
Step 4: Write the net ionic equation using the remaining ions.
Mg2+(aq) + PO4^3-(aq) → Mg3(PO4)2(s)
2) Na2CO3 + ZnCl2:
Step 1: Write the balanced molecular equation.
Na2CO3 + ZnCl2 → NaCl + ZnCO3
Step 2: Break down all the ionic compounds into their respective ions.
Na2CO3(aq) → 2Na+(aq) + CO3^2-(aq)
ZnCl2(aq) → Zn2+(aq) + 2Cl^-(aq)
NaCl(aq) → Na+(aq) + Cl^-(aq)
ZnCO3(aq) → Zn2+(aq) + CO3^2-(aq)
Step 3: Remove the spectator ions, the ions that appear unchanged on both sides of the equation.
In this case, there are no spectator ions.
Step 4: Write the net ionic equation using the remaining ions.
CO3^2-(aq) + Zn2+(aq) → ZnCO3(s)
3) Na2CO3 + Na3PO4:
Step 1: Write the balanced molecular equation.
Na2CO3 + Na3PO4 → Na2PO4 + Na2CO3
Step 2: Break down all the ionic compounds into their respective ions.
Na2CO3(aq) → 2Na+(aq) + CO3^2-(aq)
Na3PO4(aq) → 3Na+(aq) + PO4^3-(aq)
Na2PO4(aq) → 2Na+(aq) + PO4^3-(aq)
Step 3: Remove the spectator ions, the ions that appear unchanged on both sides of the equation.
In this case, all the ions are spectator ions.
Step 4: Since all ions are spectators, there is no net ionic equation for this reaction.
4) Na3PO4 + ZnCl2:
Step 1: Write the balanced molecular equation.
Na3PO4 + ZnCl2 → NaCl + Zn3(PO4)2
Step 2: Break down all the ionic compounds into their respective ions.
Na3PO4(aq) → 3Na+(aq) + PO4^3-(aq)
ZnCl2(aq) → Zn2+(aq) + 2Cl^-(aq)
NaCl(aq) → Na+(aq) + Cl^-(aq)
Zn3(PO4)2(aq) → 3Zn2+(aq) + 2PO4^3-(aq)
Step 3: Remove the spectator ions, the ions that appear unchanged on both sides of the equation.
In this case, the spectator ions are Na+ and Cl^-.
Step 4: Write the net ionic equation using the remaining ions.
3Na+(aq) + PO4^3-(aq) + Zn2+(aq) → Zn3(PO4)2(s)