Mary is making a pinata that has a ball-like shape. The pinata has a surface area of 50 square feet. Use the formula for the surface area of a sphere:
s=4(pi)^2
to find the radius of the pinata. Round your answer to the nearest hundredth.
_____ feet i got 50=39.4 but don't know what to do next and if it is right
To solve for the radius of the pinata, we can rearrange the formula for surface area of a sphere:
s = 4πr^2
Given that the surface area is 50 square feet, we can substitute the values:
50 = 4πr^2
To isolate the value of radius (r), divide both sides of the equation by 4π:
50 / (4π) = r^2
Rounding to the nearest hundredth, the value of 4π is approximately 12.57. Now we can solve for r by taking the square root of both sides:
√(50 / (4π)) = r
Using a calculator, we find that the square root of (50 / (4π)) is approximately 2.52.
Therefore, the radius of the pinata is approximately 2.52 feet.
To find the radius of the pinata, you can rearrange the formula for surface area of a sphere:
s = 4πr^2
where s is the surface area and r is the radius.
In this case, the surface area is given as 50 square feet, so you can plug in this value into the equation:
50 = 4πr^2
To solve for the radius (r), divide both sides of the equation by 4π:
50 / 4π = r^2
To isolate r, take the square root of both sides:
√(50 / 4π) = r
Now, you can simplify the expression on the right side:
r ≈ √(12.5 / π)
To find the approximate value of the radius, substitute the value of π (pi) as 3.14 or use a calculator:
r ≈ √(12.5 / 3.14)
r ≈ √3.98
r ≈ 1.99 feet (rounded to the nearest hundredth)
So, the radius of the pinata is approximately 1.99 feet.
S = 4pi(r)^2
50 = 4(3.14)r^2
50 = 12.56 r^2
Solve for r.