Physics
posted by Danny .
The Ultimate strength of a round steel rod is 630.000MPa. If a factor of safety of 5.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000cm?
ANS = kN (Round to 3 decimal places)
Safety = 5.000
Rod diameter = 3.000cm = 0.03m
Ultimate Strength
= 630.000MPa = 630000kPa
Allowable strength
= Ultimate strength/ Factor of safety
= 630000kPa/ 0.03m
= 21000000kPa
Load = Allowable strength * Area
Area = pi * d^2/ 4
= 21000000kPa * 3.1416 * 3^2/ 4
= 21000000kPa * 3.1416 * 9/ 4
= 593762400kPa/ 4
ANS = 148440.600kPa
Please check. Thank you.

Load = ultimate strength x Area/ Factor of safety=
=630•10⁶•π•0.03²/4•5=8.9064•10⁴ N=
=89.064 kN
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