Trig
posted by Helay .
Determine the number of triangles with the given parts.
b=24 c=29 B=40deg
I got 1

I get two.
make a sketch
Using the Sine Law, you will get
sinC = 29sin40/24 = .776...
so C = appr 51 degrees or 18051 = 129 degrees
(since the sine is positive in I or II)
You will be able to draw a second triangle with B = 40, C = 129 and A = 11 degrees
This is called the ambiguous case.
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