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Determine the number of triangles with the given parts.

b=24 c=29 B=40deg

I got 1

  • Trig -

    I get two.

    make a sketch
    Using the Sine Law, you will get
    sinC = 29sin40/24 = .776...
    so C = appr 51 degrees or 180-51 = 129 degrees
    (since the sine is positive in I or II)

    You will be able to draw a second triangle with B = 40, C = 129 and A = 11 degrees

    This is called the ambiguous case.

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