1) Calculate the tensile stress in a 33.000mm diameter rod subjected to a pull of 30.000kN.
ANS= MPa (Round to 3 decimal places)
Diameter = 33.000mm = 0.033m
30.000kN = 30000N
Area = pi*d^2/4
= 3.1416 * 0.033^2/ 4
= 3.1416 *0.001089/ 4
= 0.0034212024/ 4
= 8.553006*10^-4
= 0.0008553
Stress= Load/Area
= 30000/ 0.0008553
= 35075412.14Pa
= 35075.41214kPa
ANS = 35.07541214MPa
2) Consider that the rod was originally 1.000 meters long, and it was stretched 1.110mm by the pulling force. Calculate the strain produced in the rod.
ANS=(6decimal places)
1.110mm = 0.00111m
= 0.00111m/1m
ANS = 0.001110
Please check. Thank you.
No one has answered this question yet.
To calculate the tensile stress in the rod, you first need to calculate the cross-sectional area of the rod using its diameter. The formula to calculate the area of a circle is given by: Area = π * (diameter/2)^2.
In this case, the diameter is given as 33.000mm, which can be converted to meters by dividing it by 1000. So, the diameter in meters is 0.033m.
Plugging in the values into the formula, we get:
Area = π * (0.033m/2)^2 = 3.1416 * (0.033/2)^2 = 3.1416 * (0.0165)^2 = 3.1416 * 0.00027225 = 0.0008553 square meters.
Next, we need to calculate the stress. Stress is defined as the force applied per unit area. The force applied is given as 30.000kN, which can be converted to newtons by multiplying it by 1000. So, the force applied is 30000N.
Plugging in the values into the formula, we get:
Stress = Force/Area = 30000N / 0.0008553 square meters = 35075412.14 Pascals.
To convert the answer to megapascals (MPa), divide by 1,000,000:
Stress = 35075412.14 / 1,000,000 = 35.07541214 MPa (rounded to 3 decimal places).
For the second question, you need to calculate the strain produced in the rod. Strain is defined as the change in length per unit original length. To calculate strain, divide the change in length (1.110mm) by the original length (1.000m).
Converting 1.110mm to meters, we get 0.00111m.
Strain = Change in length / Original length = 0.00111m / 1.000m = 0.001110 (rounded to 6 decimal places).
So, the strain produced in the rod is 0.001110.