a person jumps from a ledge 3.7 meters and when he drops to the ground it takes .7 meters for him to stop what is the force applied to his body
a person jumps from a ledge 3.7 meters and when he drops to the ground it takes .7 meters for him to stop what is the force applied to his body . A person (46kg)
UPDATED****
To calculate the force applied to the person's body upon landing, we need to use the principles of Newton's laws of motion.
Newton's second law states that the force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a): F = m * a.
In this case, we need to find the acceleration experienced by the person when they come to a stop after dropping 3.7 meters and traveling an additional 0.7 meters.
To find the acceleration, we can use the equation for motion under constant acceleration:
v^2 = u^2 + 2as,
where v is the final velocity, u is the initial velocity (which is zero when the person starts from rest), a is the acceleration, and s is the distance traveled.
The final velocity v can be determined using the equation:
v^2 = u^2 + 2as,
v^2 = 0 + 2 * a * 4.4,
v^2 = 8.8a.
Since the person comes to a stop, the final velocity (v) is zero. Therefore, the equation becomes:
0 = 8.8a.
Simplifying, we find that a = 0 m/s².
We can now calculate the force (F) applied to the person's body using Newton's second law:
F = m * a.
However, we need to know the mass of the person in order to find the force. If we assume a mass of 75 kilograms (an average mass for an adult), we can substitute this value into the equation:
F = 75 kg * 0 m/s².
The force applied to the person's body would be 0 Newtons.
It is important to note that when using real-world scenarios, the force can be influenced by various factors such as the bending of the body upon impact, the flexibility of the surface, etc. This calculation assumes idealized conditions.