Physics

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A 3.6 kg object is accelerated from rest to a
speed of 34.4 m/s in 42 s.
What average force was exerted on the object during this period of acceleration?
Answer in units of N

  • Physics -

    average acceleration = change in speed / change it time

    = (34.4 - 0) / (42 - 0 )

    = .819 m/s^2

    Force = mass * acceleration = 3.6 *.819 = 2.95 Newtons

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