posted by Lynn .
A 3.6 kg object is accelerated from rest to a
speed of 34.4 m/s in 42 s.
What average force was exerted on the object during this period of acceleration?
Answer in units of N
average acceleration = change in speed / change it time
= (34.4 - 0) / (42 - 0 )
= .819 m/s^2
Force = mass * acceleration = 3.6 *.819 = 2.95 Newtons