precalc

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solve the following logarithmic equation:

2lnx= log base e^3 343

  • precalc -

    log base e^3 = 1/3 ln, so

    2lnx = ln e^2
    1/3 ln 343 = ln ∛343 = ln ln7
    x^2 = 7
    x = √7

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