a machine gun can fire 20 bullet persecond if speed of bullet is 100m/s and if each bullet weight 100grams calcuate force required to hold the gun in its position

To calculate the force required to hold the gun in its position while it fires 20 bullets per second, we need to consider the rate at which bullets are being fired and the momentum of each bullet.

First, let's calculate the momentum of a single bullet. Momentum (p) is calculated by multiplying mass (m) by velocity (v):

p = m * v

Given that each bullet weighs 100 grams and has a speed of 100 m/s, let's convert the mass to kilograms:

m = 100 grams = 0.1 kg

Now we can calculate the momentum:

p = 0.1 kg * 100 m/s
p = 10 kg m/s

The momentum of a single bullet is 10 kg m/s.

Since the machine gun fires 20 bullets per second, the total momentum generated by the gun in one second can be calculated by multiplying the momentum of a single bullet by the rate of fire:

Total momentum = momentum per bullet * rate of fire
Total momentum = 10 kg m/s * 20 bullets/s
Total momentum = 200 kg m/s

Now, to find the force required to hold the gun in position, we can use the equation:

Force (F) = rate of change of momentum (Δp) / time (t)

In this case, the rate of change of momentum is the total momentum generated by the gun, and the time is 1 second:

F = Δp / t
F = 200 kg m/s / 1 s
F = 200 N

Therefore, the force required to hold the machine gun in its position while it fires 20 bullets per second is 200 Newtons.