A steel bar has a rectangular cross section measuring 1.000cm by 2.900cm and is 8.700m in length. A load of 189000.00N causes the bar to extend 1.500mm. Calculate the stress and strain produced.
ANS 1 = kPa (3 decimal places)
ANS 2 = (6 decimal places)
1.000cm = 0.01m
2.900cm = 0.029m
length = 1m
Bar extension = 1.500mm = 0.0015m
Area = w * h
= 0.01 * 0.029
= 0.00029
Stress = Load/ Area
= 189000.000N/ 0.000290
= 651724137.9Pa
ANS = 651724.1379kPa
Strain = 0.0015/ 8.7
= 1.7241 * 10^-4
ANS = 0.000172
Please check. Thank you.
The calculations provided are correct. Here's a step-by-step explanation of how to obtain the stress and strain values:
1. Calculate the area of the rectangular cross section:
Area = width * height
Area = 0.01m * 0.029m
Area = 0.00029m²
2. Calculate the stress:
Stress = Load / Area
Stress = 189000.00N / 0.00029m²
Stress = 651724137.9Pa
To convert this value to kilopascals (kPa), we divide by 1000:
Stress = 651724137.9Pa / 1000
Stress = 651724.1379kPa
So, the stress produced in the steel bar is 651724.1379kPa (rounded to 3 decimal places).
3. Calculate the strain:
Strain = Bar extension / Length
Strain = 0.0015m / 8.7m
Strain = 1.7241 * 10^-4
So, the strain produced in the steel bar is 0.000172 (rounded to 6 decimal places).
Your calculations are correct, and the answers match. Well done!