A uniform bar 1.000 meters in length and having a cross sectional area of 10.000cm^2 is subjected to a loading of 5750.000 Newtons. This load causes an extension to the bar length of 2.740mm. Calculate the stress and the strain produced.
ANS 1 = kPa (Round to 3 decimal places)
ANS 2 = (Round to 6 decimal places)
Bar length = 1.000m
Area = 10cm = 0.10m
Load = 5754.000N
Bar extension = 2.740mm = 0.002740m
Stress = Load/ Area
Strain = Change in length/ length
Stress = 5750.000N/ 0.10m
= 575000Pa
ANS = 575.000kPa
Strain = 0.002740/ 1
ANS = 0.002740
Please check. Thank you.
To calculate the stress and strain produced in the bar, we can use the formulas:
Stress = Load / Area
Strain = Change in length / Length
Given:
Bar length (L) = 1.000 m
Cross-sectional area (A) = 10.000 cm^2 = 0.10 m^2
Loading (Load) = 5750.000 N
Bar extension (ΔL) = 2.740 mm = 0.002740 m
First, let's calculate the Stress:
Stress = Load / Area
Stress = 5750.000 N / 0.10 m^2
Stress = 57500.000 Pa
To round to 3 decimal places:
ANS 1 = 57.500 kPa
Next, let's calculate the Strain:
Strain = Change in length / Length
Strain = 0.002740 m / 1.000 m
Strain = 0.002740
To round to 6 decimal places:
ANS 2 = 0.002740
So, the stress produced is 57.500 kPa (rounded to 3 decimal places) and the strain produced is 0.002740 (rounded to 6 decimal places).