Math
posted by Andrey .
How do i get 2 consecutive numbers (pair numbers) that they product is 272?
4X² + 4X  272=0

h, h +1
h(h+1) = 272
h^2 + h = 272
h^2 + h 272 = 272272
h^2 + h 272 = 0
(h 16)(h + 17) = 0
h = 16
h = 17
16, 17, and 16, 17 
x = first number
y = second number
y = x + 1
x * y = 272
x * ( x + 1 ) = 272
x ^ 2 + x = 272
x ^ 2 + x  272 = 0
Solutions :
x =  17
and
x = 16
For x =  17
y = x + 1 =  17 + 1 =  16
x * y =  17 * (  16 ) = 272
For x = 16
y = x + 1 = 16 + 1 = 17
x * y = 16 * 17 = 272
So solutions are :
 17 and  16
and
16 and 17 
Yes.Both are all solution.
Proof
x(x+1)= 272
16(16+1) = 272
16(17) =272
272 = 272
17(17+1) = 272
17(16)= 272
272 = 272