The ultimate strength of a steel rod is 550.000MPa. If the factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 4.100cm?

ANS = kN (Round to 3 decimal places)

ultimate strength = 550.000MPa
Factor of safety = 3.000
Rod diameter = 4.100cm = .041m

Not sure how to find the maximum permissible load for the rod. Need some help please. Thank you.

To find the maximum permissible load for the steel rod, we can use the concept of stress and factor of safety.

1. Convert the rod diameter from centimeters to meters:
diameter = 4.100 cm = 0.041 m

2. Calculate the area of the rod using the formula for the area of a circle:
area = π * (diameter/2)^2

3. Calculate the maximum stress the rod can withstand by dividing the ultimate strength by the factor of safety:
maximum stress = ultimate strength / factor of safety

4. Calculate the maximum permissible load by multiplying the maximum stress by the area of the rod:
maximum permissible load = maximum stress * area

Let's plug in the values and calculate the maximum permissible load:

1. Convert the rod diameter from centimeters to meters:
diameter = 0.041 m

2. Calculate the area of the rod:
area = π * (0.041/2)^2

3. Divide the ultimate strength by the factor of safety to get the maximum stress:
maximum stress = 550.000 MPa / 3.000

4. Multiply the maximum stress by the area of the rod to get the maximum permissible load:
maximum permissible load = (550.000 / 3.000) * (π * (0.041/2)^2)

Now, calculate the maximum permissible load using a scientific calculator or the values of π and perform the necessary calculations.

You can round the final answer to 3 decimal places to get the result in kilonewtons (kN).