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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 5.95 m/s. The car is a distance d away. The bear is 37.0 m behind the tourist and running at 7.80 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

  • physics -

    V1*t = V2*t-37 m.
    5.95t = 7.80t-37
    7.8t-5.95t = 37
    1.85t = 37
    t = 20 s.

    d = 5.95 * 20 = 119 m

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