College Algebra

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can someone tell me if I am correct
graph y1=(1/3)^x and y2= (1/3)^x+2

the relationships between the two graphs is they are separated horizontally by 2 units

  • College Algebra -

    no, they are separated vertically.

    y1 = y2 - 2

    To separate horizontally, you need the 2nd x to be 2 less than the first.

    y1 = (1/3)^x
    y2 = (1/3)^(x-2)

    Since the new x-values are 2 less than the old ones, it's as if the y-axis had been shifted 2 units to the right.

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