Post a New Question

Discreet math

posted by .

[(pvq)^(p=>)^(q=>)]=>r[(pvq)^(p=>)^(q=>)]=>r

  • Discreet math -

    If you need a proof of the proposition/identity, please first double check the expressions.

    [(pvq)^(p=>)^(q=>)]=>r[(pvq)^(p=>)^(q=>)]=>r

    Not sure if something is missing where expression is indicated in bold. Perhaps there are other problems.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question