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Verify the identity:
sin^(1/2)x*cosx - sin^(5/2)*cosx = cos^3x sq root sin x

I honestly have no clue how to approach the sin^(5/2)*cosx part of the equation

  • Precal -

    since 5/2 = 2 + 1/2, you have
    u^5/2 = u^2 * u^1/2, and so,

    √sinx cosx - sin^2x √sinx cosx
    √sinx cosx (1-sin^2 x)
    √sinx cosx cos^2x
    √sinx cos^3x

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