algebra

posted by .

I have no idea totally lost haven't done any type of math in almost 30 years

f(x)= x^4-x^3-7x^2+x+6

all the real roots are bounded by -3 and 4. Explain why these are the upper and lower bounds

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math

    Which describes the number and type of roots of the equation x^2-625=0?
  2. Algebra II

    Which describes the number and type of roots of the equation x^2 -625=0?
  3. Algebra

    I am not sure if I did this right, it is the theorem on bounds to establish integral bounds for roots of equation. 6x^3-7x^2+7x+9=0 1 6 -7 7 9 0 6 -7 7 9 6 -1 6 0 0 0 6 -1 6 15 6 -7 7 9 -1 6 -7 7 9 -6 13 20 6 -13 20 29 answer is -1<x<1
  4. college algebra

    Use the theorem on bounds to establish the best integral bounds for the roots of the equation: w^(4)-8w^(3)+2w^(2)+10w-1=0
  5. algebra

    Given that XY =21 and 1 < x < 2, find the sum of the upper and lower bounds of Y. Express your answer as a decimal.
  6. abstract algebra

    Suppose K = {{2,3,4,5,6,7},{2,5,7,8,12},{1,2,3,5,7,9,13,20}}. Find three upper bounds for K in P(N) and three lower bounds. Does K have a least upper bound?
  7. abstract algebra

    Suppose K = {{2,3,4,5,6,7},{2,5,7,8,12},{1,2,3,5,7,9,13,20}}. Find three upper bounds for K in P(N) and three lower bounds. Does K have a least upper bound?
  8. Upper-lower bounds-solved

    find the upper and lower bounds for definite integral sign, a=1, b=6, sqrt(x) dx. partitions are as follow: x0=1, x1= 3, x2=6 of the interval [1,6] upper sum: 3sqrt(3) + 3sqrt(6) lower sum: 3sqrt(3) + 3 but this is incorrect. can someone …
  9. Sums-Calc

    find the upper and lower bounds for definite integral sign, a=1, b=6, sqrt(x) dx. partitions are as follow: x0=1, x1= 3, x2=6 of the interval [1,6] upper sum: 3sqrt(3) + 3sqrt(6) lower sum: 3sqrt(3) + 3 but this is incorrect. can someone …
  10. algebra

    if a quadratic equation with real coefficents has a discriminant of 10, then what type of roots does it have?

More Similar Questions