math
posted by raja harishchandra .
What is the sum of all possible real values of x, such that there exists a real value y which satisfies the equation (x+y−40)^2+(x−y−18)^2=0?

since all squares are >= 0, both squared expressions must be zero. So you need
x+y40 = 0 and
xy18 = 0
2x58 = 0
x = 29
y = 11
Only one real value for x satisfies the equation
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