Physic (Stress & Strain)

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1) Calculate the tension stress in a 21.00mm diameter rod subjected to a pull of 30.000kN.

21mm =0.021m
30.000kN = 30000N

A = pi*d^2/4
= 3.1416 * (0.021)^2m^2/ 4
= 3.1416 * 0.000441/ 4
= 0.0013854456/ 4
= 0.0003463614

Stress = Load/ Area
= 30000/ 0.0003463614
= 86614732.47N
= 86614.73247kN
ANS = 86.61473247MPa

2) Consider that the rod was originally 1.000m long, and is stretched 1.090mm by a pulling force. Calculate the strain produced in the rod.

1.090mm = 0.001090m

Strain = 0.00109m/ 1.000m
ANS = 0.00109m

Is these done correctly?

  • Physic (Stress & Strain) -

    Both are numerically correct.

    In #2, you divide m by m, hence no units.

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