A volleyball is spiked so that it has an initial velocity of 12.0 m/s directed downward at an angle of 53.2 ° below the horizontal. What is the horizontal component of the ball's velocity when the opposing player fields the ball?

Vo = 12m/s[53.2o].

Xo = 12*cos 53.2 = 7.2 m/s.

NOTE: The hor. component remains constant during the flight.

To find the horizontal component of the ball's velocity, we need to use trigonometry.

The initial velocity of the ball can be broken down into its horizontal and vertical components. The horizontal component represents the velocity in the x-direction, and the vertical component represents the velocity in the y-direction.

Given that the initial velocity of the ball is 12.0 m/s at an angle of 53.2° below the horizontal, we can use trigonometry to find the horizontal component.

The horizontal component can be calculated using the formula:
(horizontal component) = (initial velocity) * cos(angle)

In this case, the initial velocity is 12.0 m/s, and the angle is 53.2° below the horizontal.

(horizontal component) = (12.0 m/s) * cos(53.2°)

Now, we can calculate the horizontal component:

(horizontal component) = (12.0 m/s) * cos(53.2°)
(horizontal component) = (12.0 m/s) * 0.602
(horizontal component) ≈ 7.22 m/s

Therefore, the horizontal component of the ball's velocity when the opposing player fields the ball is approximately 7.22 m/s.