# physics

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A basketball player is running at 5.10 m/s directly toward the basket when he jumps into the air to dunk the ball. He maintains his horizontal velocity.
(a) What vertical velocity does he need to rise 0.800 meters above the floor

• physics -

v(vert) = sqrt (2gh) = =sqrt(2•9.8•0.8)=3.96 m/s

• physics -

Use kinematic equation
v^2-u^2=2as
v=0 (at 0.8m above floor)
u=unknown
a=-9.81
s=0.8
u^2=√(2*9.81*0.8)=15.696
u=4 m/s approx.

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