Calcium oxide and carbon are reacted to produce carbon monoxide and calcium carbide CaC2. When one mole of calcium carbide is formed, 464.8kJ is absorbed.
Write a thermochemical equation for this reaction.
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The thermochemical equation for this reaction can be written as follows:
CaO(s) + 3C(s) → CaC2(s) + CO(g)
ΔH = +464.8 kJ
In this equation, the solid forms of calcium oxide (CaO) and carbon (C) react to produce solid calcium carbide (CaC2) and gaseous carbon monoxide (CO). The value of 464.8 kJ represents the enthalpy change (energy absorbed) for the formation of 1 mole of calcium carbide.
To write a thermochemical equation, we need to balance the chemical equation and include the heat change (enthalpy) associated with the reaction.
First, let's write the balanced chemical equation for the reaction between calcium oxide (CaO) and carbon (C):
CaO + 3C → CaC2 + CO
Now, we need to include the heat change. Since the question states that 464.8 kJ is absorbed when one mole of calcium carbide is formed, we need to indicate this on the product side of the equation. Since the energy is being absorbed, we will add it as a reactant with a positive sign:
CaO + 3C → CaC2 + CO + 464.8 kJ
This is the thermochemical equation for the given reaction. It shows that when one mole of calcium carbide is formed, 464.8 kJ of energy is absorbed.