Math (Trigonometry [Polar Form])
posted by Shin .
Let z be a complex number such that z = 2(cos 8∘ + i cos 82∘).Then z^5 can be expressed as r(sin α∘+ i cos α∘), where r is a real number and 0 ≤ α ≤ 90. What is the value of r+α?
Hint to solve:
Example Question:
Let z be a complex number such that z = 2(cos 5∘ + i cos 85∘). Then z^6 can be expressed as r(sin α∘ + i cos α∘), where r is a real number and 0 ≤ α ≤90. What is the value of r+α?
Solution:
Since cos85∘=cos(90∘−5∘)=sin5∘,z=2(cos5∘+icos85∘)=2(cos5∘+isin5∘).
Applying De Moivre's formula gives
z^6=26(cos(6⋅5∘)+isin(6⋅5∘))=64(cos30∘+isin30∘).
Since cos30∘=cos(90∘−60∘)=sin60∘ and sin30∘=sin(90∘−60∘)=cos60∘,
z^6=64(cos30∘+isin30∘)=64(sin60∘+icos60∘).
Therefore, r=64 and α=60, hence r + α = 64 + 60 = 124.
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